Compare the oscillations in an LC circuit are analogous to the oscillation of a block at the end of a spring.

Explanation

The LC oscillation is similar to the mechanical oscillation of a block attached to a spring. The lower part of each figure in question no. 22 depicts the corresponding stage of a mechanical system.
Differential equation of LC oscillation,
`(d^(2)q)/( dt^(2))+( q)/( LC) =0` or ` (d^(2)q)/(dt^(2)) + omega_(0)^(2) q = 0` for a block of mass m oscillating with frequency `omega_(0)` the equation is,
`(d^(2)x)/(dt^(2))+omega_(0)^(2) = 0` or ` (d^(2) x)/( dt^(2)) + ( Kx)/( m ) = 0 `
Here `omega_(0) = sqrt((k)/( m))` and k is the spring constant.
From F = kc in mechanics `k = ( F )/( x ) ` means the external force requires to produce unit extension or compression is known as force constant.
Unit of force constant `Nm^(-1)`.
Corresponding equation of this equation in LC circuit is` V = (q)/( C )`
`:. (1)/(C ) = ( V )/(q)` means for established unit charge, necessary electrical difference is `(1)/( C )`.
In below table analogies between mechnical and electrical quantities are shown.
`{:("Mechanical system","Electrical system"),("Mass m","Inductance L"),("Force constant k","Reciprocal capacitance "1//C),("Displacement x","Charge q"),("Velocity" v=(dx)/(dt),"Current" I = ( dq)/(dt)),("Mechanical energy" E = (1)/(2) kx^(2) + ( 1)/(2) m v^(2),"Electromagnetic energy" E = ( 1)/(2) (q^(2))/(C ) kx^(2) + ( 1)/(2) m v^(2) ):}`