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A light bulb is rated at 100W for a 220 ...

A light bulb is rated at 100W for a 220 V supply. Find the peak voltage of the source

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We know, `V_("rms") = (V_(m))/(sqrt(2))`
`rArr` Peak voltage `V_(m) = sqrt( 2) V_(rms)`
`:. V_(m) = ( 1.414) (220)` `( :.` Here `V_(rms) = V =220 ` Volt)
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KUMAR PRAKASHAN-ALTERNATING CURRENTS -SECTION B NUMERICALS (TEXTUAL ILLUSTRATIONS)
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