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In series LCR circuit, the plot of I"max...

In series LCR circuit, the plot of `I_"max"` vs `omega` as shown in figure. Find the bandwidth and mark in the figure.

Text Solution

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The magnitude of current flowing in circuit is `1/sqrt2` time of maximum value, the two frequencies obtained is `omega_1` and `omega_2`.
`therefore I_"rms" = ((I_"rms")_"max")/sqrt2`=0.7 A
At resonance frequency, current is maximum. Hence in below graph it is obtained as `omega_1` and `omega_2`.

From graph diagram corresponding frequencies are 0.8 rad/s and 1.2 rad/s for `omega_1` and `omega_2`.
So, Bandwidth `Deltaomega=omega_2-omega_1`
=1.2-0.8
=0.4 rad/s
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