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An alternating voltage given as V=200sqr...

An alternating voltage given as `V=200sqrt2sin (100t)V` is applied to a capacitor of 1 `mu`f. The current reading of the ammeter will be equal to ...... mA.

A

100

B

20

C

40

D

80

Text Solution

Verified by Experts

The correct Answer is:
B
`I_m=V_m/"|Z|"`
but `|Z|=1/(omegaC)=1/(100xx10^(-6))=1/10^(-4)`
Now `I_(rms)=I_m/sqrt2 =V_m/(sqrt2|Z|)=(200sqrt2)/(sqrt2xx1/(10^(-4)))`
`=200xx10^(-4) =20xx10^(-3)` Amp = 20 mA
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