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An LCR series circuit with L =0.5H, C=10...

An LCR series circuit with L =0.5H, `C=10xx10^(-6) F, R=100 Omega` is connected to an A.C. source of frequency of 50 Hz. The impedance of the circuit is …….

A

1.8765 `Omega`

B

18.76 `Omega`

C

189.6 `Omega`

D

101.3 `Omega`

Text Solution

Verified by Experts

The correct Answer is:
C

`omega=2pif=2xx3.14xx50`=314 rad/sec
`|Z|=sqrt(R^2+(omegaL-1/(omegaC))^2)`
`=sqrt((100)^2+[314xx0.5-1/(314xx10^(-5))]^2)`
`|Z|=sqrt(10^4+[157-50000/147]^2)`
`therefore |Z|=189.6 Omega`
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