When 10 A current passes through 12`Omega` resistance, maximum voltage across it is ……..

Options

A. 20 V
B. 90 V
C. 169.68 V
D. 120 V

Answer

C

Explanation

In case of current `I_(dc)=I_(ac)=I_(rms)=I_m/sqrt2` (where `I_(rms)`=rms value of current and `I_m` = maximum current )
Similarly in case of voltage `V_(dc)=V_(ac)=V_(rms)=V_m/sqrt2` (where `V_(rms)`= rms value of voltage and `V_m` = maximum voltage )
`I_m=sqrt2I_(rms)`
=1.414 x 10
=14.14 A
`therefore` Max. voltage `V_m=I_m R`
=14.14 x 12
= 169.68 V