Above graphs are for reactance versu frequency of A.C. emf's frequency. Then ......

Options

A. Figure (1) is for inductor and figure (2) is for capacitor.
B. Figure (1) is for capacitor and figure (2) for inductor.
C. Figure (1) is for resistance and figure (2) is for capacitor.
D. Figure (1) is for inductor and figure (2) is for resistor.

Answer

B

Explanation

`therefore` Capacitive reactance `X_C=1/(omegaC)` and inductive reactance `X_L=omegaL`
`therefore X_C prop 1/omega " " therefore X_L prop omega`
`therefore X_C prop 1/(2piv) therefore X_L prop 2piv`
`therefore X_C prop 1/v` and `X_L prop v`
Here `X_Cv` = constant is an equation of hyperbol and so for capacitor, graph of `X_C to v` is like hyperbola given in figure (1).
Here `X_L = Kv + 0` is an equation of a straight line passing through origin and so graph of `X_L to` is like a straight line given in figure (2).