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In an A.C. circuit of frequency 400/pi H...

In an A.C. circuit of frequency `400/pi` Hz is of capacitance `CmuF` and reactance of capacitance is `25Omega` then the value of C = .....

A

`25muF`

B

`50muF`

C

`400muF`

D

`100muF`

Text Solution

Verified by Experts

The correct Answer is:
B
`f=400/pi` Hz, `X_C=25Omega`
`omega=2pif =2pixx400/pi`=800 rad/s
`X_C=1/(omegaC)`
`therefore C=1/(omegaX_C)=1/(800xx25)`
`therefore C=1/20000=50xx10^(-6) F = 50 muF`
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