An alternating voltage V = 400 sin (500o...

An alternating voltage V = 400 sin (500`omega`t)V is connected to a 0.2 `kOmega` resistor, what will be the rms value of current ?

14.14 A

1.414 A

0.1414 A

`2A`

Text Solution

Verified by Experts

The correct Answer is:

Comparing equation V=400 sin `(500omegat)` with `V=V_m sin omegat`,
`V_m`=400 V `therefore V_"rms"=V_m/sqrt2`
`I_"rms"=V_"rms"/R=V_m /(sqrt2R)=400/(sqrt2xx200)`
`=2/sqrt2=sqrt2`=1.414 A

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