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A 220 V, 50 Hz a.c. source is connected ...

A 220 V, 50 Hz a.c. source is connected an inductance of 0.2 H and a resistance of 20 `Omega` in series. What is the current in the circuit ?

A

`10A`

B

`5A`

C

`33.3A`

D

`3.33A`

Text Solution

Verified by Experts

The correct Answer is:
A
`|Z|=sqrt(R^2+omega^2L^2)`
`=sqrt(400+2500xx0.04)`
`I=V/"|Z|"`
`=sqrt(400+100)`
`=220/22.36`
`=sqrt500`
`therefore` I=9.84 A `approx` 10.0 A
`therefore |Z|=22.36 Omega`
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