A coil of resistance R and inductance L is joined with a battery of E volt. The current passing through it will be ………..

Options

A. `E/R`
B. `E/L`
C. `sqrt(E^2/(R^2+L^2))`
D. `sqrt((EL)/(R^2+L^2))`

Answer

A

Explanation

When D.C. emf of E volt applied to a circuit, `omega = 0 therefore X_L = omegaL = 0`. So inductor act as a conductor.
`therefore` Impedance of circuit
`therefore I=E/"|Z|" " " |Z|=R`
`therefore I=E/R`