In an A.C. circuit, voltage applied is V = 220 sin 100t. If the impedance is 110`Omega` and phase difference between current and voltage is `60^@`, the power consumption is equal to ........

Options

A. 50 W
B. 110 W
C. 220 W
D. 330 W

Answer

B

Explanation

Comparing equation V=220 sin 100t with
`V=V_m sin omegat`,
`V_m`=220
`|Z|=110 Omega`
`therefore I_m=V_m/"|Z|"=220/110`=2A
`delta=60^@ =pi/3` rad
`P=(V_mI_m)/2 cos delta =(220xx2)/2 cos 60^@`
`=(220xx2)/2 xx1/2`=110 W