In the given figure, total V"rms" and I"...

In the given figure, total `V_"rms"` and `I_"rms"` passing from various components in circuit are shown. Then total `I_"rms"`= ……

`I=I_R+I_L+I_C`

`I=I_R+I_L-I_C`

`I=sqrt(I_R^2 +(I_L-I_C)^2)`

`I=sqrt(I_R^2 +(I_C -I_L)^2)`

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Verified by Experts

The correct Answer is:

Voltage and current diagram of phasor is as shown in the figure.

From fig.
`I^2=I_R^2 +(I_L-I_C)^2`
`therefore I=sqrt(I_R^2+(I_L -I_C)^2)`

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