An alternating voltage is connected in series with a resistor R and an inductor L. If the potential drop across the resistor is 200 V and across the inductor is 150 V, then what is the applied voltage ?

Options

A. 350 V
B. 250 V
C. 500 V
D. 300 V

Answer

B

Explanation

`V^2=V_R^2 +V_L^2`
`therefore V=sqrt(V_R^2 +V_L^2)`
`=sqrt((200)^2 + (150)^2)`
`=sqrt(40000+22500)`
`=sqrt62500`
`therefore` V=250 V