For resonance in above circuit angular frequency and amplitude of current are respectively.....and ……

Options

A. 2500 rad `s^(-1)` and `5sqrt2A`
B. 2500 rad `s^(-1)` and 5A
C. 2500 rad `s^(-1)` and `5/sqrt2` A
D. 250 rad `s^(-1)` and `5sqrt2` A

Answer

A

Explanation

Series angular frequeny ,
`omega_r=1/sqrt(LC)`
`omega_r=1/sqrt(8xx10^(-3)xx20xx10^(-6))`
`omega_r=1/sqrt(16xx10^(-8))=10^4/4 =2500 "rad s"^(-1)`
Here current `I_0=V_0/R = (sqrt2V_"rms")/R`
`I_0=(sqrt2xx220)/44=5sqrt2`A