A 10Omega resistance, 5mH inductor and 1...

A 10`Omega` resistance, 5mH inductor and 10`muF` capacitor are joined in series. When a suitable frequency of alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency ……

is halved

is doubled

remains unchanged

in quadrupled

Text Solution

Verified by Experts

The correct Answer is:

At resonance `omegaL=1/(omegaC)`
`therefore omega=1/sqrt(LC)` , where there is no term of resistance so on changing the value of resistance there will no change of `omega`.

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