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If number of turns in primary and second...

If number of turns in primary and secondary coils is increased to two times each, the mutual inductane .....

A

becomes four times

B

becomes two times

C

becomes `1/4` times

D

remains unchanged

Text Solution

Verified by Experts

The correct Answer is:
A
`N._1=2N_1,N._2=2N_2`
Mutual inductance =`M=phi/I=(mu_0 N_1N_2A)/l`
`therefore M prop N_1N_2`
`therefore M_2/M_1=(N._1N._2)/(N_1N_2)=((2N_1)(2N_2))/(N_1N_2)=4`
`therefore M_2=4M_1`
`therefore` Mutual inductance becomes four times.
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