A low loss transformer has 250 V applied to primary and gives 4.6 V in secondary. The secondary is connected to a load which draws 5A current. The current flowing in primary is ………

Options

A. 0.1 A
B. 1.0 A
C. `10 A`
D. 250 A

Answer

A

Explanation

`epsilon_1`=250 V, `epsilon_2`= 4.6 , `I_2`= 5A, `I_1` = ?
`P_1=P_2` (For an ideal transformer )
`epsilon_1I_1=epsilon_2I_2`
`therefore I_1=(epsilon_2I_2)/epsilon_1=(4.6xx5)/250` = 0.092 A
`therefore I_1 approx` 0.1 A