The voltage of an A.C. source varies with time according to the equation `V = 100 sin 100pit cos100pit`, where t is in second and V is in volt, then .......

Options

A. the peak voltage of the source is 100 V
B. the peak voltage of the source is 50 V
C. the peak voltage of the source is `100/sqrt2`V
D. the frequency of the source is 50 Hz.

Answer

B

Explanation

V=100 sin 100 `pit` cos 100 `pit`
=50 (2 sin 100 `pi`t cos 100 `pit`)
=50 sin (200`pi`t) comparing this eqn. with
`V=V_m sin omegat`
`therefore V_m`=50 V, `omega=200pi` rad/s , f=100 Hz.