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A lamp consumes only 50% of maximum powe...

A lamp consumes only 50% of maximum power applied in an A.C. circuit. What will be the phase difference between applied voltage and circuit current ?

A

`pi/6` rad

B

`pi/3` rad

C

`pi/4` rad

D

`pi/2` rad

Text Solution

Verified by Experts

The correct Answer is:
C
`P=P_m cos delta`
`therefore cos delta =P/P_m =P_(m//2)/P_m=1/2`
`therefore delta = pi/3` radian
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