Home
Class 12
MATHS
Sketch the region {(x,0) //y = sqrt( ...

Sketch the region `{(x,0) //y = sqrt( 4-x^2)}` and X- axis . Find the area of the region using integration.

Text Solution

Verified by Experts

The correct Answer is:
`2 pi` seq. unit
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    KUMAR PRAKASHAN|Exercise SOLUTIONS OF NCERT EXAMPLAR PROBLEMS ( LONG ANSWER TYPE QUESTIONS)|8 Videos
  • APPLICATION OF INTEGRALS

    KUMAR PRAKASHAN|Exercise SOLUTIONS OF NCERT EXAMPLAR PROBLEMS ( OBJECTIVE TYPE QUESTIONS)|11 Videos
  • APPLICATION OF INTEGRALS

    KUMAR PRAKASHAN|Exercise TEXTBOOK ILLUSTRATIONS FOR PRACTICE WORK|15 Videos
  • APPLICATION OF DERIVATIVES

    KUMAR PRAKASHAN|Exercise PRACTICE PAPER - 6 (SECTION - D)|2 Videos
  • BOARD'S QUESTION PAPER MARCH - 2020

    KUMAR PRAKASHAN|Exercise PART - B (Section - C)|4 Videos

Similar Questions

Explore conceptually related problems

Draw a rough sketch of the region { (x,y) //y^2 le 6 ax and x^2 + y^2 = 16 a^2 } .Also find the area of the region sketched using method of integration .

Sketch the region for y=sin(x-[x]) .

Find the area of the region {(x,y) |x^2 le y le x} .

Draw a rough sketch of the given curve y=1 + |x+1|,x =-3 , x =3 , y=0 and find the area of the region bounded by them , using integration

find the area of the region bounded by y= sqrt(x) and y=x .

The area of the region bounded by the curve y= sqrt(3x +4), x - axis and x=-1 and x=4 is A. the area of the region bounded by the curve y^2 = 3x +4 , X - axis and x=-1 and x=4 is B. then A : B =……..

Find the area of the region bounded by the parabola y=x^2 and y=|x|

The area of the region bounded by the curve y= sqrt(16 -x^2) and X- axis is ……..

Find the area of the region bounded by the parabola y = x^(2) and y = |x|.

Find the area of the region bounded by the curve y^2 = 4x and x^2 = 4y