Fraction of molecules crossing activation energy barrier =` e^(-x)` Determine x
[`E_a` =80.3Kj/mol, T=700K,R=8.314J/moleK]

The activation energy for the reaction: 2AB rarr A_(2)+B_(2)(g) is 159.7 kJ mol^(-1) at 500 K . Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy. (Given: 2.3 xx 8.314 J K^(-1) mol^(-1) xx 500 K = 9561.1 J mol^(-1) )

Rate of reaction in absence of catalyst at 700 K is same as in presence of catalyst at 500 K. If catalyst decreases activation energy barrier by 30 kJ/mole, determine activation energy in presence of catalyst. (Assume 'A' factor to be same in both cases)

If the activation energy of a reaction is 80.9 kJ mol^(-1) , the fraction of molecules at 700 K, having enough energy to react to form products is e^(-x) . The value of x is ______ ((Rounded off to the nearest integer) [Use R=8.31JK^(-1)mol^(-1) ]

The rate of a reaction quadruples when the temperature changes from 300 to 310 K. The activation energy of this reaction is : ( Assume Activation energy and pre-exponential factor are independent of temperature, ln(2) = 0.693, R = 8.314J - mol^(-1) K^(-1))

A first order reaction is 50% complete in 30 minutes at 27^(@) C and in 10 minutes at 47^(@) C. Calculate the reaction rate constants at these temperatures and the energy of activation of the reaction in kJ//mol (R=8.314 J mol^(-1)K^(-1))

What is the fraction of molecules having energy equal to or greater than activation energy, E_(a) ? What is this quantity called ?