If A and B are two events then show that...

If A and B are two events then show that
(i) `(P(AnnB^(c)))=P(A)-P(AnnB)`
(ii) The probability that exactly one of them occurs is given by `P(A)+P(B)-2P(AnnB)`

Verified by Experts

The correct Answer is:

(i) `(A nn B sube A)`
(ii) `P(A) + P(B) - 2P(A nn B)`

Similar Questions

Explore conceptually related problems

If A,B are two events, then show that P((A)/(B))P(B)+P((A)/(B^(C)))P(B^(C))=P(A).

If A and B are two events of a sample space then P(A)-P(B)=

If A and B are two events such that P(A)=(1)/(2) and P(B)=(2)/(3) then

A and B are two events such that P(A)=0.58 P(B) =0.32 and P(A cap B)=0.28 .Then the probability that neither A nor B occurs is

If A and B are two events such that P(A uu B)=0.65, P(A nnB)=0.15 then P(barA)+P(barB) =

If A and B are two events such that P(A)=1//4, P(B)=1//2, P(uuB)=5//8 then P(A nn B) =

If A and B are two independent events such that P(AnnB)=1//6 and P(AnnB')=1//3 then P(A)=

If P(A)=0.5 , P(B)=0.3 and P(AnnB)=0.1 then find the probability that exactly one of A, B happen.