If `E_(1),E_(2)` are two events with `E_(1)capE_(2)=phi` then show that `P(E_(1)^(C)capE_(2)^(C))=P(E^(C))-P(E_(2))`

E_(1) , E_(2) are events of a sample space such that P(E_(1))=(1)/(4) , P((E_(2))/(E_(1)))=(1)/(2) , P((E_(1))/(E_(2)))=(1)/(4) then P((E_(1))/(E_(2)))+P((E_(1))/(barE_(2)))=

E_(1) , E_(2) are events of a sample space such that P(E_(1))=(1)/(4) , P((E_(2))/(E_(1)))=(1)/(2) , P((E_(1))/(E_(2)))=(1)/(4) then P((barE_(1))/(E_(2)))=

If E_(1), E_(2), are independent events, such that P(E_(1) cap E_(2)) = 1//4, P(overlineE_(1) cap overlineE_(2)) = 1//4 , then P(E_(1))+P(E_(2))=

If E_(1), E_(2), are independent events, such P(E_(1) cap E_(2))= 1//8, P(overlineE_(1) cap overlineE_(2) ) = 1//4 , then P((E_(1)+P(E_(2))=

If E_(1), E_(2) are independent events in a random experiment with P(E_(1) cap E_(2)) =1//8 , P(overlineE_(1) cap overlineE_(2)) = 3//8 , then P(E_(1)), P(E_(2)) =

The two events E_(1), E_(2) are such that P(E_(1)uuE_(2))=5/8, P (bar(E)_(1))=3/4, P(E_(2))=1/2 , then E_(1) and E_(2) are

An urn contains four balls bearing numbers 1,2,3 and 123 respectively . A ball is drawn at random from the urn. Let E_(p) i = 1,2,3 donote the event that digit i appears on the ball drawn statement 1 : P(E_(1)capE_(2)) = P(E_(1) cap E_(3)) = P(E_(2) cap E_(3)) = (1)/(4) Statement 2 : P_(E_(1)) = P(E_(2)) = P(E_(3)) = (1)/(2)

Suppose that E_1 and E_2 are two events of a random experiment such that P(E_(1))=1/4 , P(E_2 |E_2) =1/2 and P(E_1 |E_2)=1/4 . Observe the lists given below : The correct matching of the list I from the list II is :