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An unbiased die with faces 1, 2, 3, 4, 5...

An unbiased die with faces 1, 2, 3, 4, 5, 6 is thrown n times and the list of 'n' numbers showing up is noted. What is the probability that among the numbers 1, 2, 3, 4, 5, 6 exactly two numbers appear in this list.

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The correct Answer is:
`(15(2^(n) - 2))/(6^(n))`
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