Home
Class 12
MATHS
If the difference between the mean and v...

If the difference between the mean and variance of a Binomial variae is 5/9 then find the probability for the event of 2 successes when the experiment is conducted 5 times.

Text Solution

Verified by Experts

The correct Answer is:
`(80)/(243)`
Promotional Banner

Topper's Solved these Questions

  • RANDOM VARIABLES

    AAKASH SERIES|Exercise Exercise 4.1|18 Videos

  • RANDOM VARIABLES

    AAKASH SERIES|Exercise Exercise 4.2|14 Videos

  • RANDOM VARIABLE

    AAKASH SERIES|Exercise PRACTICE EXERCISE|34 Videos

  • REVISION EXERCISE

    AAKASH SERIES|Exercise STRAIGHT LINES|24 Videos

Similar Questions

Explore conceptually related problems

If the difference between the mean and variance of a Binomial variate is 5/9 then find the probability for the event of 2 success when the experiment is conducted 5 times.

If the differnce between the mean and variance of a buinomial distribution for 5 trials is 5//9 , then the distribution is

If the difference between mean and variance of a binomial distribution is 2 and the mean of X is 6, then the number of trials is

The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes is

If the mean and variance of a binomial distribution are 4 and 2 respectively , then the probability of 2 successes of that binomial variate X , is

If the mean and variance of a binomial variate X are (4)/(3),(8)/(9) respectively , then P(X = 2) =

If the mean and variance of a Binomial variable X are (5)/(2) and (5)/(4) respectively, then P(X gt 1)=

A : If the difference between the mean and variance of a binomial distribution for 5 trials is 5//9 then the distribution o is (2//3+1//3)^(5) R : The binomial distribution with parameters n, p is (q+p)^(n)

The probability of happening of an event in a trial is 0.5. The probability of happening of the event atlest once if the experiment is repeated 3 times is