If normal chord a point 't' on the parabola `y(2)=4ax` subtends a right angle at vertex, then prove that `t=+_sqrt(2)`

If a normal chord of a puint on the parabola y^(2) = 4ax , subtends a right angle at the vertex, then t =

If a normal chord at a poit t( ne 0) on the parabola y^(2) = 9x subtends a right angle at its vertex, then t =

If the normal chord drawn at the point P(t) to the parabola y^(2) = 4ax subtends a right angle at the focus, then show that , = pm2

If a normal chord of a parabola y^(2) = 4ax subtends a right angle at the origin, then the slope of that normal chord is

If P (at_(1)^(2),2at_(1)) and Q (at_(2)^(2),2at_(2)) are two variable points on the curve y^(2)=4ax and PQ subtends a right angle at the vertex then t_(1)t_(2) =