The product of the perpendiculars from the foci on any tangent to the ellipse `x^(2)//a^(2)+y^(2)//b^(2)=1` is

Prove that the product of the perpendicular from the foci on any tangent to the ellips (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 is equal to b^(2)

The product of the perpendicular from the foci on any tangent to the hyperbola x^(2) //a^(2) -y^(2) //b^(2) =1 is

The product of the perpendicular distances drawn from the foci to any tangent of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is (gtb)

The sum of the squares of the perpendiculars on any tangent to the ellipse x^(2)//a^(2)+y^(2)//b^(2)=1 from two points on the minor axis each at a distance sqrt(a^(2)-b^(2)) from the centre is

Prove that the product of the lengths of the perpendicular drawn from foci on any tangent to the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 is b^(2)

The product of the perpendicular from any point on the hyperbola x^(2) //a^(2) -y^(2)//b^(2) =1 to its asymptotes is

Statement-I : The distance of the normal to x^(2) + 2y^(2) = 5 at (1,sqrt(2)) from origin is 1/3sqrt(2) . Statement-II : The product of the perpendiculars from the foci of the ellipse (x^(2))/(7)+(y^(2))/(4)=1 to any tangent is 7. Statement-III: The distance between the foci of (x^(2))/(25)+(y^(2))/(36)=1 is 2sqrt(11) . The Statements that are correct are :