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Find the locus of the point which is at ...

Find the locus of the point which is at a constant distance of 5 units from (4,-3).

Text Solution

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The correct Answer is:
`x^(2)+y^2-8x+6y=0`
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Knowledge Check

  • The locus of a point which is at a distance of 5 unit from (2,1,-3) is

    A
    `x^2+y^2+z^2+2x+4z+5=0`
    B
    `x^2+y^2+z^2+2x-4z-20=0`
    C
    `x^2+y^2+z^2-2x-4z+5=0`
    D
    `x^2+y^2+z^2-4x-2y+6z-11=0`
  • The locus of the point which is at a distance 5 unit from ( -2, 3 ) is

    A
    ` x ^ 2 - y^ 2 + 4 x - 6y + 12 = 0 `
    B
    ` x ^ 2 + y ^ 2 + 4 x - 6y - 12 = 0 `
    C
    ` x ^ 2 - y ^ 2 + 4 x - 6 y - 12 = 0 `
    D
    ` x ^ 2 + y ^ 2 + 4x - 6y + 1 2 = 0 `
  • The locus of the point which is at a distance 5 unit from x - axis is

    A
    ` y ^ 2 + 25 = 0 `
    B
    ` y ^ 2 - 25 = 0 `
    C
    ` y + 25 = 0 `
    D
    ` y - 25 = 0 `
  • Similar Questions

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    Find the equation of locus of a point which is at a distance 5 from A (4, - 3).

    The locus of the point which is at a distance of '3' unit from zx-plane is

    The locus of a point which is at a distance of 2 unit from yz - plane is

    The locus of a point which is a distance of '5' unit from xy-plane is

    The locus of all points that are at a distance of atleast 2 units from (-3,0) is