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Find the equation to the locus of points...

Find the equation to the locus of points equidistant from the points
(i) (-3,2), (0,4)
(ii) (a+b,a-b),(a-b,a+b)

Text Solution

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The correct Answer is:
`6x + 4y- 3 =0`
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A: The equation to the locus of points which are equidistant from the points ( - 3, 2 ) , (0, 4 ) is 6x + 4y - 3 =0 . R : The locus of points which are equidistant to A, B is perpendicular bisector of AB