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The plane 2x + 3y + kz - 7 = 0 is parall...

The plane 2x + 3y + kz - 7 = 0 is parallel to the line whose d.r's are (2,-3,1) then k=

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Find k if the plane 2x+3y+kz=7 is perpendicular to the line with direction ratios (4, 6, -1) .

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Knowledge Check

  • The plane 2x + 3y + kz – 7 =0 is parallel to the line whose direction ratios are (2, -3, 1) then k=

    A
    5
    B
    8
    C
    1
    D
    0

  • The plane x+2y-kz+3=0 is perpendicular to the line whose direction ratio are (2,4,3) then k =

    A
    5
    B
    `10/3`
    C
    1
    D
    0

  • A: The plane 2x + 3y + 5 = 0 is parallel to x-axis. R: The plane ax + by + cz +d=0 is parallel to x-axis if a = 0.

    A
    both A and R are true and R is the correct explanation of A
    B
    both A and R are true but R is not the correct explanation of A
    C
    A is true but R is false
    D
    A is false but R is true

    • Similar Questions

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    If the planes 2x + 3y + 4z + 7 = 0 and 4x + ky + 8z + 1 = 0 are parallel then k =

    The equation of the plane through the line of intersection of the planes 2x + 3y + 4z - 7 =0, x + y +z – 1 = 0 and perpendicular to the plane x – 5y + 3z – 2 = 0) is

    If the plane 2x-3y+5z-2=0 divides the line segment joining the points (1,2,3) and (2,1,k) in 9:11 then k =

    The equation of the plane passing through the point (- 1, 2, 4) and parallel to the plane 2x + 3y - 5z + 6 = 0 is

    If the planes 2x+3y-z+5=0, x+2y-kz+7=0 are perpendicular then k =

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