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If S=[(0,1,1),(1,0,1),(1,1,0)], A=(1)/(2...

If `S=[(0,1,1),(1,0,1),(1,1,0)], A=(1)/(2)[(b+c,c-a,b-a),(c-b,c+a,a-b),(b-c,a-c,a+b)]`, then `SAS^(-1)=`

A

`[(a,0,0),(0,b,0),(0,0,c)]`

B

`(1)/(2)[(a,0,0),(0,b,0),(0,0,c)]`

C

`2[(a,0,0),(0,b,0),(0,0,c)]`

D

`3[(a,0,0),(0,b,0),(0,0,c)]`

Text Solution

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The correct Answer is:
A
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Knowledge Check

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    0
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    1
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    D
    `(ad-bc)I`

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