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OABC is a tetrahedron D and E are the mi...

OABC is a tetrahedron D and E are the mid points of the edges `bar(OA) and bar(BC)`. Then the vector `bar(DE)` in terms of `bar(OA),bar(OB)` and `bar(OC)`.

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The correct Answer is:
`bar(AL)=bar(AB)+1/2bar(AD), bar(AM)=1/2bar(AB)+bar(AD)`
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