A
B
C
D
Text Solution
Verified by Experts
The correct Answer is:
Topper's Solved these Questions
PROPERTIES OF VECTORS
AAKASH SERIES|Exercise PRACTICE EXERCISES|55 VideosPROPERTIES OF VECTORS
AAKASH SERIES|Exercise EXERCISE - I|31 VideosPROPERTIES OF TRIANGLES
AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL II) (Linked Comprehension Type Questions Passage -III:)|3 VideosRATE MEASUREMENT
AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - 1) (LEVEL - 1) (STRAIGHT OBJECTIVE TYPE QUESTION)|43 Videos
Similar Questions
Explore conceptually related problems
AAKASH SERIES-PROPERTIES OF VECTORS-EXERCISE - II
- The median AD of the triangle ABC is bisected at E. BE meets AC in F t...
Text Solution
|
- If S is the circumcentre, G the centroid, O the orthocentre of Delta A...
Text Solution
|
- If S is the circumcentre, O is the orthocentre of Delta ABC then vec(O...
Text Solution
|
- The P.V.'s of the vertices of a DeltaABC are bar(i)+bar(j)+bar(k), 4ba...
Text Solution
|
- The P.V.'s of the vertices of a triangle are 2bar(i)+3bar(j)+4bar(k), ...
Text Solution
|
- DeltaABC be an equilateral triangle whose orthocentre is the origin 'O...
Text Solution
|
- The P.V.'s of A, B, C are bar(i)+bar(j)+bar(k), 4bar(i)+bar(j)+bar(k),...
Text Solution
|
- In a DeltaABC, P.V.'s of midpoints of AB, AC are bar(i)-bar(j)+bar(k),...
Text Solution
|
- The vectors of bar(AB)=3bar(i)+4bar(k) and bar(AC)=5bar(i)-2bar(j)+4ba...
Text Solution
|
- If D, E, F are the midpoints of BC, CA, AB of Delta ABC, then vec(A)D ...
Text Solution
|
- If D, E and F are respectively the mid-points of AB, AC and BC in Delt...
Text Solution
|
- If ABCD is a parallelogram then bar(AC)+bar(BD)=
Text Solution
|
- ABCD is a parallelogram, with AC, BD as diagonals, then overset(-)(AC)...
Text Solution
|
- OACB is a parallelogram with bar(OC)=bar(a), bar(AB)=bar(b)" then "bar...
Text Solution
|
- If the diagonals of a parallelogram are bar(i)+5bar(j)-2bar(k) and -2b...
Text Solution
|
- ABCD is a quadrilateral. E is the point of intersection of the line jo...
Text Solution
|
- ABCDE is a pentagon then bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(ED)+bar...
Text Solution
|
- ABCDEF is a regular hexagon. If bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(...
Text Solution
|
- ABCDEF is a regular hexagon. bar(AB)+bar(AC)+bar(AD)+bar(EA)+bar(FA)...
Text Solution
|
- ABCDEF is a regular hexagon. If bar(AB)=bar(a), bar(BC)=bar(b)" then...
Text Solution
|