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ABCDE is a pentagon then bar(AB)+bar(A...

ABCDE is a pentagon then
`bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(ED)+bar(AC)=`

A

`3bar(AC)`

B

`bar(AC)`

C

`2bar(AC)`

D

`4bar(AC)`

Text Solution

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The correct Answer is:
A
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