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"cosec"h^(-1) ((3)/(2))+"cosec"h^(-1)(-(...

`"cosec"h^(-1) ((3)/(2))+"cosec"h^(-1)(-(1)/(2))=`

A

`log_(e)((2+sqrt(13))/(3))`

B

`log_(e)(sqrt(5)-2)`

C

`log((2+sqrt(13))/(3(sqrt(5)+2)))`

D

`log_(e)2`

Text Solution

Verified by Experts

The correct Answer is:
C
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sec^(-1)(-3/2)+cosec^(-1)(-3/2)=(pi)/2

Find "sec h"^(2)(tanh^(-1) ((1)/(5)))+"cosec"h^(2)(coth^(-1)2)

Knowledge Check

  • "cosec h"^(-1)((1)/(5)) =

    A
    `log (sqrt(26) + 5)`
    B
    `log(5+sqrt(27))`
    C
    `log(26+sqrt(5))`
    D
    `log(27+sqrt(5))`
  • sec h^(-1) ((1)/(2)) - "cosec h"^(-1) ((3)/(4)) =

    A
    `log_(e) ((1+ sqrt(3))/(3))`
    B
    `log_(e) ((2 + sqrt(3))/(3))`
    C
    `log_(e) ((2-sqrt(3))/(3))`
    D
    `log_(e) [3 (2 + sqrt(3))]`
  • "cosec h"^(-1) ((1)/(5)) =

    A
    `log (sqrt(26) + 5)`
    B
    `log (5 + sqrt(27))`
    C
    `log (26 + sqrt(5))`
    D
    `log (27 + sqrt(5))`
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    Show that "sec"^(2)(Tan^(-1)2)+"cosec"^(2)(Cot^(-1)2) =10

    sec h^(2)[tan h^(-1)((1)/(2))] + "cosec " h^(2) (cot h^(-1)(3)) =

    sec^(2)(tan^(-1)(2))+cosec^(2)(cot^(-1)(2))=

    sec h^(2) [tan h^(-1) ((1)/(2))] + "cosec h"^(2) (cot h^(-1) (3)) =

    Sec^(2)(Tan^(-1)(2))+Cosec^(2)(Cot^(-1)(2))=