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("cosh x")/("1 -tanhx") + ("sinh x")/( "...

`("cosh x")/("1 -tanhx") + ("sinh x")/( "1 - coth x")` =

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I : ("tanh x")/("sech x - 1") + ("tanh x ")/("sech x + 1") + " 2 cosech x = 0" "II :" ("cosh x")/("1 - tanh x") + ("sinh x")/("1 - coth x")="sinh x + cosh x "

("cosh x - 1")/("sinhx") =

("1+ tanhx")/("1-tanhx") =

(cosh(x))/(1-tanh(x))+(sinh(x))/(1-coth(x))=

("cosh x +sinh x")^n =

(sinh(2x))/(1+cosh(2x))=

("cosh x + 1")/("cosh x -1") = "coth "^2x/k, "then k"=

Show that (cosh(2x)-1)/(sinh(2x)) = (sinh(2x))/(1+cosh(2x))=tanhx

If cosh 2x = 199, then coth x =