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"Sech"^(-1) (sin theta)=...

`"Sech"^(-1) (sin theta)=`

A

`log("cos"(theta)/(2))`

B

`log("sin"(theta)/(2))`

C

`log("cos"(theta)/(2))`

D

`log("cot"(theta)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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