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The temperature of an ideal gas is incre...

The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K, the root mean square velocity of the gas molecules is v, then at 480 K, it will be

A

4v

B

2v

C

`v//2`

D

`v//4`

Text Solution

Verified by Experts

The correct Answer is:
B
Since M remains the same, so `v_(rms)propsqrt(T)`
`therefore (v_(1))/(v_(2))=sqrt((T_(1))/(T_(2)))=sqrt((120)/(480))=sqrt((1)/(4))=(1)/(2)`
`v_(2)=2" " [because v_(1)=v]`
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