Home
Class 12
PHYSICS
For a gas molecule with 6 degrees of fre...

For a gas molecule with 6 degrees of freedom, the law of equipartition of energy gives the relation between the molar specific heat `(C_(V))` and gas constant (R ) is

A

`C_(V)=(R )/(2)`

B

`C_(V)=R`

C

`C_(V)=2R`

D

`C_(V)=3R`

Text Solution

Verified by Experts

The correct Answer is:
D
As, `C_(v)=(f)/(2)R`, where f is the degree of freedom.
Here, `f=6 therefore C_(v)=(6)/(2)R=3R`
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (MCQ)|7 Videos

  • KINEMATICS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|1 Videos

  • LAWS OF MOTION

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 3: ONE OR MORE THAN ONE OPTION CORRECT TYPE (2 MARKS))|2 Videos

Similar Questions

Explore conceptually related problems

For a gas molecule with 6 degrees of freedom,the law of equipartion of energy gives the following relation between the molecular specific heat (C_(V)) and gas constant (R)

Molar specific heat of a monatomic gas at constant pressure is

Using the law of equipartition of energy , obtain a relation between the degrees of freedom f and the specific heat ratio gamma of a polyatomic gas.

State first law of thermodynamics. On its basis establish the relation between two molar specific heat for a gas.

The molar specific heat at constant pressure of monoatomic gas is

Mayer's kformula for the relation between two principla specific heats C_(p) "and " C_(V) of a gas is given by

A molecule of a gas has six degrees of freedom Then , the molar specific heat of the gas at constant volume is

The degrees of freedom of a molecule of a triatomic gas are