In Young's double slit experiment, fringes of certain width are produced on the screen kept at a certain distance from the slits. When the screen is moved away from the slits by 0.1m, fringe width increases by `6xx10^(-5)m`. The separation between the slits is 1 mm. calculate the wavelength of the light used.

Explanation

We have `beta=(lambdaD)/(d)`
In the first case `beta=(lambdaD)/(d)`
In the second case
`beta^(1)=beta+6xx10^(-5)=(lambda(D+0,1))/(d)`
`beta^(1)=beta+6xx10^(-5)=(lambdaD)/(d)+(lambdaxx0.1)/(d)`
`beta^(1)=beta+6xx10^(-5)=beta+(lambdaxx0.1)/(d)`
`lambda=(dxx6xx10^(-5))/(0.1)`
d=1mm
`lambda=(1xx10^(-3)xx6xx10^(-5))/(0.1)=6000A^(@)`