(a) Three resistors of resistance `2Omega,3Omega and 4Omega` are combined in series. What is the total resistance of the combination ?
(b) It this combination is connected to a battery of emf 10 V and negligible internal resistance, obtain the potential drop across each resistor.

Explanation

`R_(1)=2omega,R_(2)=3omega,R_(3)=4omega,R_(s)=?`
(a)In series ,effective resistance
`R_(s)=R_(1)+R_(2)+R_(3)=2+3+4=9omega`
(b)Current through the circuit is
`I=(epsi)/(R_(s)+r)=(10)/(9)(because r=0)`
I=1.11A
`therefore` Potential drop across =`1R_(1)=2xx1.11=2.22V`
Potential drop across =IR_(2)=3xx1.11=3.33V`
Potentia drop across `R_(3)=IR_(3)=4xx1.11=4.44V`