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A bullet is fired gun. The force on bull...

A bullet is fired gun. The force on bullet is `F=600-2xx10^(5)t` newton. The force reduces to zero just when bullet leaves barrel. Find he impulse imparted to bullet

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`F=600-2xx10^(5)t`
F becomes zero as soon as the bullet leaves the barrel. `0 = 600-2xx10^(5)t, 6=2xx10^(5)t`
`t=3xx10^(-3)s` Impusle `= int_(0)^(t)Fdt`
`= int_(0)^(t)(600-2xx10^(5)t)dt=[600t-cancel(2)xx10^(5)(t^(2))/(cancel(2))]^(3xx10^(-3))`
`= 600xx3xx10^(-3)-10^(5)xx9xx10^(-6)=0.9 Ns`
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