An isolated particle of mass 'm' is at rest in a horizontal plane (x-y) along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4, the speed of heavier fragments is `V_(0)` horizontally at the instant of explosion. At an instant `t_(0)` later, the smaller fragment is at `y = y_(0)` below the point of projection. Then

Options

A. The horizontal separation between the two fragments is `3V_(0) t_(0)` at that instant `t_(0)`
B. The horizontal separation between the two fragments is `2V_(0) t_(0)` at that instant `t_(0)`
C. The speed of the smaller fragment at the instant `t_(0)` is `sqrt(V_(0)^(2) + 2g y_(0))`
D. The speed of the smaller fragment at the instant `t_(0)` is `sqrt(9V_(0)^(2) + 2g y_(0))`

Answer

A, D