Home
Class 11
CHEMISTRY
An alkane with mol.mass = 86 on brominat...

An alkane with mol.mass = 86 on bromination gives only two monobromo derivatives (excluding stereoisomers). The alkane is

A

`(CH_3)_2CHCH_2CH_2CH_3`

B

`(CH_3)_3C-CH_2CH_3`

C

`(CH_3)_2CH-CH(CH_3)_2`

D

`(CH_3)_4C`

Text Solution

Verified by Experts

The correct Answer is:
C
The alkane with mol. Mass 86 is hexane `(C_6H_(14))` 2,3-Dimethylbutane, i.e., Option (c) has only two types of hydrogens and hence forms two monobromo derivatives
Promotional Banner

Topper's Solved these Questions

  • HYDROCARBONS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - I (LEVEL-II ( MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS )))|10 Videos

  • HYDROCARBONS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - I (LEVEL-II ( LINKED COMPREHENSION TYPE QUESTIONS ( PASSAGE-I))))|2 Videos

  • HYDROCARBONS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - I (LEVEL-I ( STRAIGHT OBJECTIVE TYPE QUESTIONS )))|18 Videos

  • GENERAL ORGANIC CHEMISTRY

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|35 Videos

  • HYDROGEN AND ITS COMPOUNDS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|20 Videos