Propene reacts with alkaline KMnO4 in co...

Propene reacts with alkaline `KMnO_4` in cold condition gives

propan -1 ,2-diol

propan-1,3-diol

propan-1,2,3-triol

none

Text Solution

Verified by Experts

The correct Answer is:

`CH_3 - CH = CH_2 + [O] + H_2O underset(KmNO_4) overset("cold , alkalines")to CH_3- underset(OH)underset(|)(C)H - underset(OH)underset(|)CH_2` propan -1,2-diol

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