An alcohol (a) on dehydration gives (b), which on Ozonolysis gives acetone and formaldehyde. (b) decolourises alkaline `KMnO_4` solution but (a) does not. (a) and (b) are respectively:

Options

A. `CH_3CH_2CH_2CH_2OH and CH_3CH_2CH=CH_2`
B. `CH_3CH_2-overset(OH)overset(|)CH-CH_3 and CH_3-CH = CH-CH_3`
C. `(CH_3)_3 C - OH and (CH_3)_2 C = CH_2`
D. `CH_3 - CH_2 - overset(OH)overset(|)CH-CH_3 and (CH_3)_2C = CH_2 `

Answer

C

Explanation

`underset((A))((CH_3)_3C-OH) underset(-H_2O)to underset((B))(CH_3 - underset(CH_3)underset(|)C = CH_2)`,
`CH_3 - underset(CH_3)underset(|)C = CH_2 overset(O_3)to underset(CH_3)underset(|)CH_3 - C = O + HCHO`