`CH_3Br + CH_3CH_2Br overset(Na//"dry either")to` product. Possible product in the above reaction .

Options

A. `CH_3CH_2CH`
B. `CH_4`
C. `CH_3CH_2CH_2CH_3`
D. `CH_2=CH_2`

Answer

A, B, C, D

Explanation

This reaction following freedical mechanism `overset(*)(C)H_3 & CH_3 overset(*)CH_2`, are the intermediate freeradicals
`overset(*)(C)H_3 + overset(*)CH_3 to CH_3 , overset(*)CH_3 + CH_2CH_3 to CH_3CH_2CH_3,`
`CH_3 overset(*)(C)H_2 + overset(*)(C)H_2 CH_3 to CH_3CH_2CH_2CH_3`

`CH_3 + CH_3 - CH_3 to underset((b))(CH_4) + CH_3-CH_2`