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The correct Answer is:
A-R ; B-S ; C-Q ; D-P
`CH_2 = CHBr to H -= CH-(R) NaNH_2`
`CH_3C -= C CH_3 to CH_3CO - COCH_3 -(S)O_3 // Zn`
`CH_2 = CH_2 to HOCH_2 - CH_2OH`
`-(Q)` Dil . Alkaline `KMnO_4`
`C_6H_5 MgBr to C_6H_6 - (P) H_2O`
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