A column of 0.05 M Na0H solution of diameter 1cm and length 1m has resistance `1.11xx10^(4)` ohm. Caluclate the resistivity, conductivity and molar conductivity.

Explanation

Area `= a = pi r^(2) = (22//7) (0.5 cm)^(2)`
`=7.85xx10^(-5)m^(2)`.
Length `= 1= 1m`. Resistance `=R = 1.11xx10^(4)`.
Resistivity `= rho = R a/l = (1.11xx10^(4)xx7.85xx10^(-5))/(1) = 0.871 Omega m`
Conductivity `= k =rho^(-1) = (0.871 ohm m )^(-1) = 1.15 Sm^(-1)`.
Molar conductivity `= mu = (k xx 1000)/("molarity") = (1.15)/(0.05xx1000)`
`= 2.3 xx 10^(-2) S m^(2) mol^(-1)`.